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12X^2-192X+576=0
a = 12; b = -192; c = +576;
Δ = b2-4ac
Δ = -1922-4·12·576
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-192)-96}{2*12}=\frac{96}{24} =4 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-192)+96}{2*12}=\frac{288}{24} =12 $
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